n^2-12n+43=7

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Solution for n^2-12n+43=7 equation: 



n^2-12n+43=7

We move all terms to the left:

n^2-12n+43-(7)=0

We add all the numbers together, and all the variables

n^2-12n+36=0

a = 1; b = -12; c = +36;
Δ = b2-4ac
Δ = -122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{12}{2}=6$

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